4x^2+11x-20=20

Solution for 4x^2+11x-20=20 equation:

4x^2+11x-20=20

We move all terms to the left:

4x^2+11x-20-(20)=0

We add all the numbers together, and all the variables

4x^2+11x-40=0

a = 4; b = 11; c = -40;
Δ = b2-4ac
Δ = 112-4·4·(-40)
Δ = 761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{761}}{2*4}=\frac{-11-\sqrt{761}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{761}}{2*4}=\frac{-11+\sqrt{761}}{8}
$